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What is the angular velocity of a body on'the surface of the earth at the equator ? Also find its linear velocity. Given radius of the earth is 6400 km. Period of rotation of the earth = 24 hours.

Answer»


SOLUTION :`omega = 2pi//t = 2pi//24 XX 60 xx 60 = 7.26 xx 10^(-5) "rad/s", v = romega = 6400 xx 10^(3) xx 7.26 xx 10^(-5) = 465 m//s`


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