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what is the approximate volume of Naoh when the standard solution of oxalic acid is 100ml and 0.1 molarity |
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Answer» Answer:Oxalic acid has the FORMULA C2H2O4 (HOOC-COOH) so it is diprotic . Therefore, the equivalent weight of crystalline oxalic acid = 63. If you prepare 1.0 N solution of oxalic acid, you need to dissolve 6.30 g of it in ENOUGH distilled water to have a solution with total volume of 100 mL. Place the oxalic acid solution in a flask with few drops of an indicator (ph.ph can be used). Pour the volume you select for 0.1 N solution (it is the same as 0.1 M solution) of NaOH in the buret but since it is still not standardized, the concentration will be considered as unknown. Add NaOH solution titrant to the analyte until the end point is reached. Apply the equation N x V (oxalic acid) = N' x V' (NaOH), where N,V, and V' are known. Find out N' which will not be far from 0.1 (probably 0.13 to 0.97 ). Use the NaOH normality you get for CITRIC acid estimation by titration. Explanation: |
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