1.

Answer»

Solution

I : Let base of the triangle = $4x$ m

=> Height of triangle = $\frac{3}{4} \TIMES 4x = 3x$ m

There is no other info, so I alone is insufficient.

Similarly, II alone is also insufficient.

Combining both STATEMENTS, and using pythagoras theorem, we get :

=> $(3x)^2 + (4x)^2 = (5^2)$

=> $9x^2 + 16x^2 = 25$

=> $X^2 = \frac{25}{25} = 1$

=> $x = \sqrt{1} = 1$

=> Base = 4 m and height = 3 m

$\therefore$ Area of triangle = $\frac{1}{2} \times 3 \times 4 = 6 m^2$

Thus, both statements together are sufficient.


Discussion

No Comment Found

Related InterviewSolutions