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What is the arrangement of atoms in the lattice structure of diamond and give contribution of each C atom ?

Answer»

SOLUTION :Diamond is a covalent ctystal in which each C -atom is` sp^(3)` hybridized. THUS, each C-atom is covalently bonded to four othertetrahedrally. These tetrahedra are linked together into a three dimesionalgiant molecule.
The structureof diamond is similar to that of ZnS ( in which `S^(2-)`ions form fcc lattice and `ZN^(2+)` ions are present on the body diagonals and occupy alternate tetrahedral voids).
In diamond, we have C-atoms is place of ` Zn^(2+) and S^(2-)`ions. Thus, diamond has face - centred cubic STRUTURE in which C -atoms are present at the corners as well as face- centres and alternatetetrahedral voids.
Contribution of C- atoms at the corners = ` 8 xx 1/8=1`
Contribution of C-atoms at face-centres = ` 6 xx 1/2 =3`
As four C -atoms are present on the body diagonals i.e, in the alternate tetrahedral voids, their contribution = 4.
Total no. of C -atomsin the unit cell =1+3+ 4= 8 .


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