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What is the atomic weight of an element X for which a sample containing `1.58xx10^(22)` atoms weigh 1.05 g?A. 28 gB. 20 gC. 40 gD. 23 g

Answer» Correct Answer - C
We know that one mole of an element
`= 6. 02 xx 10^(23)` atoms
= atomic weight of the element
Now, `1.58xx 10^(22)` atoms weigh `.05` g
`therefore 6.02 xx 10^(23)` atoms weigh `= ((1.05xx6.02xx10^(23)))/(1.58 xx 10^(22)) = 40 ` g
Atomic weight of `X=40` g


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