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What is the average of all the one digit, two digit and three digit natural numbers?1). 3002). 5003). 10004). 1250 |
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Answer» As we know, all the one digit, two digit, and 3-digit natural numbers are from 1 – 999 ? SUM of n natural numbers = n(n + 1)/2 Sum of 999 natural numbers = (999 × 1000)/2 = 499500 ∴ REQUIRED AVERAGE = 499500/999 = 500 |
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