1.

What is the average of all the one digit, two digit and three digit natural numbers?1). 3002). 5003). 10004). 1250

Answer»

As we know, all the one digit, two digit, and 3-digit natural numbers are from 1 – 999

? SUM of n natural numbers = n(n + 1)/2

Sum of 999 natural numbers = (999 × 1000)/2 = 499500

REQUIRED AVERAGE = 499500/999 = 500


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