1.

What is the b.p of an aquoues solution whose freezing point is -2.48^(@)C ?(K_(f)=1.86^(@)C kg// mol, K_(b)=0.512^(@)C.kg//mol)

Answer»

`100.7^(@)C`
`102.5^(@)C`
`109.0^(@)C`
`99.3^(@)C`

Solution :`(DELTA T_(F))/(Delta T_(B))=(K_(f))/(K_(b))`


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