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What is the binding energy per nucleon of `_(6)C^(12)`nucleus? Given , mass of `C^(12)` `(m_(c))_(m)` = 12.000 u Mass of proton `m_(p)` = 1.0078 u Mass of neutron `m_(n)` = 1.0087 u and 1 amu = 931.4 MeVA. 5.26 MeVB. 6.2 MeVC. 4.65 MeVD. 7.68 MeV |
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Answer» Correct Answer - D Binding energy per nucleon `([{m_(p)Z+m_(n)(A-Z)}-M]xx931)/("Mass number A")` `=((6xx1.0078+6xx1.0087-12)/(12))xx931.4` = 7.68 MeV |
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