What is the bond order in carbon monoxide ?

1.	What is the bond order in carbon monoxide ?
Answer» Solution :`(SIGMA1S^(2)sigma^(**)1s^(2)sigma2s^(2)sigma...2s^(2)pi2p_(X)^(2)-=pi2p_(y)^(2)sigma2p_(Z)^(2))` Bond order = `1/2=(N_(B)-N_(a))=1/2(10-4)=3.0`

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