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what is the bond order of carbon momoxide ? |
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Answer» Correct Answer - 3 `(sigma1s^(2) sigma^(*) 1s^2 sigma2s^(2) sigma^(*) 2s^(2) pi 2p_(x)^(2) -= pi2 p_(z)^(2) sigma_y^(2) sigma2 p_(z)^()2)` Bond order ` = (1)/(2) (N_b-N_a) = (1)/(2) (10- 4) = 3.0`. |
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