1.

What is the chance of getting 7 or 11 with two dice ?

Answer»

S = {(1, 1), (2, 2), ... , (6, 6)}

n(S) = 36

E = getting 7 or 11

= {(1, 6), (2, 5), (3, 4), (4, 3), (5,2), (6, 1), (5, 6), (6, 5)}

n(E) = 8

p(E) = n(E)/n(S) = 8/36 = 2/9



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