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What is the chance of getting 7 or 11 with two dice ? |
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Answer» S = {(1, 1), (2, 2), ... , (6, 6)} n(S) = 36 E = getting 7 or 11 = {(1, 6), (2, 5), (3, 4), (4, 3), (5,2), (6, 1), (5, 6), (6, 5)} n(E) = 8 p(E) = n(E)/n(S) = 8/36 = 2/9 |
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