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What is the change in oxidation number and electric charge in following balance redox reaction CuS+SO_(4)^(2-)toCuO+SO_(2) ? |
Answer» Solution : `CuS+3SO_(4)^(-2)+6H^(+)toCuO+4SO_(2)^(-)+3H_(2)O` Change in oxidation number = 6, Charges = 0 |
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