1.

What is the change in oxidation number and electric charge in following balance redox reaction CuS+SO_(4)^(2-)toCuO+SO_(2) ?

Answer»

`4.-4`
2. 0
4, -6
`6, 0`

Solution :
`CuS+3SO_(4)^(-2)+6H^(+)toCuO+4SO_(2)^(-)+3H_(2)O`
Change in oxidation number = 6, Charges = 0


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