What is the compressibility facto (Z) for 0.02 mole of a van der Waal's gas at pressure of 0.1 atm. Assume the size of gas molecules is neligible. Given : RT = 20 L. atm "mol^(-1) and alpha = 1000 atm L^(2) "mol^(-2)

What is the compressibility facto (Z) for 0.02 mole of a van der Waal'

1.	What is the compressibility facto (Z) for 0.02 mole of a van der Waal's gas at pressure of 0.1 atm. Assume the size of gas molecules is neligible. Given : RT = 20 L. atm "mol^(-1) and alpha = 1000 atm L^(2) "mol^(-2)
Answer» 2 1 0.02 0.5 Solution :`[0.1 + (100 + (0.02)^2)/(V^2)] = 20 XX 0.02` `0.1 V^2 - 0.4 V + 0.4 = 0`. `= V^2 - 4V + 4 = 0 implies V = 2L` `Z = (PV)/(nRT) = (0.1 xx 2)/(20 xx 0.02) = 0.5`.