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What is the concentration of `CH_(3)COOH` which can be added to `0.5M HCOOH` solution so that dissociation of both is same. `K_(CH_(3)COOH) = 1.8 xx 10^(-5), K_(HCOOH) = 2.4 xx 10^(-4)`

Answer» `HCOOH hArr H^(o+) + HCOO^(Theta)`
`CH_(3)COOH hArr H^(o+) + CH_(3)COO^(Theta)`
Since both are present in a mixture and therefore,
`[HCOO^(Theta)]` by `HCOOH = [CH_(3)COO^(Theta)]` by `CH_(3)COOH`
`C_(1)alpha_(1) = C_(2)alpha_(2)`
`sqrt((K_(a_(1))C_(1))) = sqrt((K_(a_(2))C_(2)))`
`:. sqrt((2.4 xx 10^(-4) xx 0.5)) = sqrt((1.8 xx 10^(-5)xxC))`
`:. C_(CH_(3)COOH) = 6.66M`


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