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What is the concentration of sugar (C_(12)H_(22)O_(11)) in mol L^(–1) if its 20 g are dissolved in enough water to make a final volume up to 2L? |
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Answer» Solution :Molar mass of sugar `=(12 xx 12) + (1 xx 22) + (11 xx 16) = 342 g mol^(-1)` Number of moles in 20 g of sugar `=20/342= 0.0585` `THEREFORE` Molar concentration of sugar solution `=("Number of moles of sugar DISSOLVED")/("Volume of solution in litres") = 0.0585/2 = 0.02925 mol L^(-1)` |
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