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What is the concentration of sugar (C_(12)H_(22)O_(11)) in mol L^(-1) if its 20 g are dissolved in enough water to make a final volume up to 2 L ? |
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Answer» Solution :Molar MASS of sugar `(C_(12)H_(22)O_(11))=12xx12+22xx1+11xx16=342gmol^(-1)` `"No. of moles in 20 G of sugar "=(20g)/(342gmol^(-1))=0.0585 " mole"` `"VOLUME of solution= 2 L(Given)"` `"Molar conentraction "=("Moles of solute")/("Volume of sol in L")=(0.0585mol)/(2L)=0.0293molL^(-1)` `=0.0293M` |
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