What is the correct expression for the phase angle in an RLC series circuit?(a) φ=tan^-1(XL-XC)/R(b) φ=tan^-1 (XL+XC)/R(c) φ=tan(XL-XC)/R(d) φ=tan^-1 (XL-XC)The question was posed to me in examination.The doubt is from Alternating Current in an RLC Circuit topic in portion Single Phase Series Circuits of Basic Electrical Engineering

What is the correct expression for the phase angle in an RLC series ci

1.	What is the correct expression for the phase angle in an RLC series circuit?(a) φ=tan^-1(XL-XC)/R(b) φ=tan^-1 (XL+XC)/R(c) φ=tan(XL-XC)/R(d) φ=tan^-1 (XL-XC)The question was posed to me in examination.The doubt is from Alternating Current in an RLC Circuit topic in portion Single Phase Series Circuits of Basic Electrical Engineering
Answer» RIGHT ANSWER is (a) φ=tan^-1(XL-XC)/R To elaborate: from the IMPEDANCE TRIANGLE we get tanφ=(XL-XC)/R. Hence φ=tan^-1 (XL-XC)/R.

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