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What is the current efficiency of an electro-deposition of copper is deposited of copper metal from `CuSO_(4)` solution in which `9.80 g` copper is deposited by the passage of `5` ampere current for `2` hour? |
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Answer» `(w)/(E) = (i.t)/(96500)` `(9.8)/(63.5//2) = (i xx 2 xx 60 xx 60)/(96500)` `i = 4.14` ampere `:.` Current efficiency `= ("Theoretical valule of I")/("Practical value of I") xx 100` `= (4.14)/(5) xx 100 = 82.8%` |
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