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What is the de Broglie length of an electron,which is accelerated from the rest,through a potential difference of 100v? |
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Answer» Solution :Potential difference =b=100v Potential energy=eV=`1.609xx10^(-19)cxx100` `1/2mv^(2)=1.609xx10^(-19)XX100` `1/2mv^(2)=1.609xx10^(17)J` `v^(2)=(2xx1.609xx10^(-10))/(m)` m=mass of elctron`=9.1xx10^(-31)KG` `:.v^(2)=(2xx1.609xx10^(17))/(9.1xx10^(-31))` `:.v=SQRT(2xx1.609xx10^(-17))/(9.1xx10^(31))`=`sqrt(2xx1.609xx10^(-17)xx10^(31)/(9.1)` `v=sqrt(3.218xx10^(14)/(9.1)` `v=5.93xx10^(6)m/s` `gamma=h/(MV) Where h=6.62xx10^(-34)JS` `=(6.62xx10^(-34))/(9.1xx10^(-31)xx5.93xx10^(6))` `1.2xx10^(-10)m` `gamma=1.2A` |
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