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What is the de Broglie wave lenght of an electron, which is accelerated from the rest, through a potential difference of 100 V? |
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Answer» SOLUTION :POTENTIAL difference = 100 V `=100xx1.6xx10^(-19)J` `lamda=(H)/(sqrt(2mev))` `=(6.626xx10^(-34)KGM^(2)s^(-1))/(sqrt(2xx9.1xx10^(-31)kgxx100xx1.6xx10^(-19)J))` `lamda=1.22xx10^(10)m` |
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