1.

What is the de Broglie wave lenght of an electron, which is accelerated from the rest, through a potential difference of 100 V?

Answer»

SOLUTION :POTENTIAL difference = 100 V
`=100xx1.6xx10^(-19)J`
`lamda=(H)/(sqrt(2mev))`
`=(6.626xx10^(-34)KGM^(2)s^(-1))/(sqrt(2xx9.1xx10^(-31)kgxx100xx1.6xx10^(-19)J))`
`lamda=1.22xx10^(10)m`


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