1.

What is the de Broglie wavelength (in cum) of a 160g cricket ball travelling at 140 Km hr^(-1).

Answer»

Solution :160g=.0.16kg.
v=velocity of the criket ball=`140Km HR^(-10)`
`=(140xx5)/(18)=38.88ms^(-1)`
de Broglie equation=gamma=`h/(MV)`
h=planck.s constant=`6.626xx10^(34)kgm^(2)s^(-1)`
de Broglie wavelength `=6.626xx10^(-34)cancel(kg m^(2) s^(-1))/(cancel(0.16kgxx38.88)cancel(ms^(-1)))`
`gamma=6.626xx(10^(-34))/(6.2208)`
`gamma=1.065xx10^(-34)m`
wavelength in cum`=1.065xx10^(-34)XX100`
`=1.065xx10^(32)cm(or) 1.065xx10^(-34)m`


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