1.

What is the degree of hardness of a sample of water containing 6 mg of MgSO_4 (molecular mass 120) per kg of water ?

Answer»


Solution :6 mg of `MgSO_4` present in `10^3` g of water
`10^6` g water will contain
` =6000 mg` of `MgSO_4`
`120 g "of " MgSO_4`= 100 g of `CaCO_3`
So, 6g of `MgSO_4 = 100/120 XX 6 = 5G " of " CaCO_3`, i.e., Hardness= 5 PPM
`LiH + H_2O to LIOH + H_2`


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