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What is the density of `N_(2)` gas at `227^(@)C and 5.00 atm` pressure? `(R= 0.0821 atm K^(-1)mol^(-1))`A. `0.29 g//ml`B. `1.40 g//ml`C. `2.81g//ml`D. `3.41 g//ml`

Answer» Correct Answer - D
Given `P= 5.00 atm, R= 0.0821 atm K^(-1)mol^(-1)`
`T=227+273= 500 K, M_(N_(2))=28`
Density`=(PM)/(RT)= (5xx28)/(0.0821xx500)= 3.41 g//ml`


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