1.

What is the difference between higher heating value and lower heating value if the product has 5 moles of H2O and Enthalpy of vaporization is 10 J/mole at standard conditions?(a) 10 J(b) -10 J(c) 50 J(d) -50 J

Answer» Correct answer is (c) 50 J

To explain I would say: HHV – LHV = 5*10 = 50 J.


Discussion

No Comment Found

Related InterviewSolutions