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What is the difference between higher heating value and lower heating value if the product has 5 moles of H2O and Enthalpy of vaporization is 10 J/mole at standard conditions?(a) 10 J(b) -10 J(c) 50 J(d) -50 J |
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Answer» Correct answer is (c) 50 J To explain I would say: HHV – LHV = 5*10 = 50 J. |
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