1.

What is the dimensional formula of specific resistance in terms of charge Q?A. `M^(1)L^(2)T^(-2)Q^(-1)`B. `M^(1)L^(2)T^(-2)Q^(-2)`C. `M^(1)L^(3)T^(-1)Q^(-2)`D. `M^(1)L T^(-2)Q^(-1)`

Answer» Correct Answer - c
`R=(rhoL)/(A) therefore rho=(RA)/(L)=(V)/(I)(A)/(L)" "(because R=(V)/(I))`
But `I=Q//t and V=(W)/(Q)`
`therefore rho=(W)/(Q)xx(A)/(L)xx(t)/(Q)=(WAt)/(Q^(2)L)`
`because [rho]=(M^(1)L^(2)T^(-2)xxL^(2)xxT^(1))/(Q^(2)xxL^(1))`
`therefore [rho]=[M^(1)L^(3)T^(-1)Q^(-2)]`


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