1.

What is the dimensional formula of thermal conductivity?

Answer»

`[MLT^(-1)K^(-1)]`
`[MLT^(-3)K^(-1)]`
`[M^(2)LT^(-3)K^(-2)]`
`[ML^(2)T^(-2)K]`

Solution :Coefficient of THERMAL conductivity is `K= (DeltaQ xx L)/(A(T_(1)-T_(2))Deltat)`….(i)
Substituiting DIMENSIONS for corresponding quantities in equation (i), we get `[K] = ([ML^(2)T^(-2)][L])/([L^(2)][K][T])= [MLT^(-3)K^(-1)]`


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