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What is the discrete-time signal obtained after sampling the analog signal x(t)=cos(2000*pi*t)+sin(5000*pi*t) at a sampling rate of 5000 samples/sec?(a) cos(2.5*pi*n)+sin(pi*n)(b) cos(0.4*pi*n)+sin(pi*n)(c) cos(2000*pi*n)+sin(5000*pi*n)(d) none of the mentionedThis question was addressed to me during an internship interview.My question comes from A2D and D2A Converters in section DSP – Basic Signaling of Digital Signal Processing

Answer»

The correct choice is (b) COS(0.4*pi*n)+sin(pi*n)

Easy explanation: From the given ANALOG SIGNAL, F1=1000Hz F2=2500Hz and Fs=5000Hz

=>f1=F1/Fs and f2=F2/Fs

=>f1=0.2 and f2=0.5

=>x(n)=cos(0.4*pi*n)+sin(pi*n).



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