1.

What is the displacement of the point of a wheel initially in contact with the ground when the wheel rolls forward half a revolution ? Take the radius of the wheel as R and the x-axis as the forward direction?

Answer»

Solution :From FIGURE , during HALF REVOLUTION of the wheel , the point A covers `piR(=AC)` horizontal distance while `2R(=BC)` vertical distance
so here , `P=piR, Q=2R`
`:."Displacement", b=sqrt(P^(2)+Q^(2))`
`=sqrt((piR^(2))+(2R)^(2))=Rsqrt(pi^(2)+4)`
and `THETA =n Tan ^(-1)(Q/P)=Tan ^(-1)((2R)/(piR))=Tan ^(-1)(2/pi)`with x-axis.
i.e., Displacement has magnitude `Rsqrt(pi^(2)+4)` and makes an angle `Tan^(-1)(2/pi)`with x-axis.


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