Saved Bookmarks
| 1. |
What is the distance of separation between 3rd and 4th orbit of H-atom? |
|
Answer» Distance of 3rd orbit d3 = \(\frac{52.9\times n^2}{z}\) = \(\frac{52.9\times(3)^2}{1}\) = 476.1 pm Distance of 2nd orbit d2 = \(\frac{52.9\times n^2}{z}\) = \(\frac{52.9\times(2)^2}{1}\) = 211.6 pm \(\therefore\) Distance of separation between 3rd and 4th orbit of H-atom = Distance of 3rd orbit – Distance of 2nd orbit from the nucleus = 476.1 − 211.6 = 264.5 pm |
|