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What is the effective radius factor when radius of curvature is 4 times the radius of earth?(a) 4(b) 4/3(c) 3(d) 3/4I have been asked this question in my homework.The origin of the question is Space Wave Propagation in chapter Space Wave Propagation of Antennas

Answer»

The correct answer is (b) 4/3

Easy explanation: EFFECTIVE RADIUS factor k in terms of radius of curvature rcand radius of EARTH re is

\(k=\frac{1}{1-\frac{r_e}{r_c}} \)

The radius of curvature is four times the radius of earth. rc=4re

⇨ K=1/(1-(1/4)) =4/3

The effective radius factor of earth is 4/3 times actual radius of earth.



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