1.

What is the empirical formula of vanadium oxide if 2.74 g of metal oxide contains 1.53g of metal?

Answer»

`V_(2)O_(3)`
VO
`V_(2)O_(5)`
`V_(2)O_(7)`

Solution :% of `V=(1.53)/(2.74)xx100=55.83`
`therefore % "of" O=44.17`
`{:("Element",%,"Atomic ratio","SIMPLEST ratio"),(V,55.83,(55.83)/(52)=1.1,(1.1)/(1.1)=1),(O,44.17,(44.17)/(16)=2.76,(2.76)/(1.1)=2.5):}`
`V:O=2:5`
Thus, empirical formula =`V_(2)O_(5)`.


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