InterviewSolution
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InterviewSolution
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What is the energy released in the fission of 2 kg of Uranium 235? (Given: energy per fission = 200 MeV)(a) 1.64 × 10^14 J(b) 1.64 × 10^15 J(c) 2.64 × 10^14 J(d) 1.64 × 10^20 JI got this question in an interview for internship.Origin of the question is Nuclear Force topic in section Nucleus of Physics – Class 12 |
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Answer» RIGHT choice is (a) 1.64 × 10^14 J For explanation I would say: Given: ENERGY PER fission = 200 MeV; For Uranium 235: The number of atoms in 235 g = 6.023 × 10^23 So, the number of atoms in 2 kg of Uranium 235 = \( ( \frac {2000}{235} )\) × 6.023 × 10^23 N = 5.125 × 10^24 Therefore, the energy released in fission of 2 kg of Uranium 235 is: E = 200 MeV × N × 1.6 × 10^-19 J E = 200 × 10^6 × 5.125 × 10^24 × 1.6 × 10^-19 J E = 1.64 × 10^14 J |
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