1.

What is the equation of the plane through z-axis and parallel to the line (x-1)/costheta=(y+2)/sintheta=(z-3)/0?

Answer»

`x COT THETA +y=0`
`x tan theta-y=0`
`x+y cot theta=0`
`x-y tan theta=0`

Solution :Let equation of plane through z-axis is
`ac+by=0`
It is given that this plane is PARELLEL to the line
`(x-1)/costheta=(y+2)/SINTHETA=(z-3)/0`
Since the plane parallel to the line
`:. Acostheta=-bb sin theta=0`
`rArr a cos theta =-b sin thetarArr a = -b tan theta`
`:.-b tan thetax +by =0`
`rArr x tan theta-y=0 (`:' b ne 0`)
Which is REQUIRED equation of plane.


Discussion

No Comment Found

Related InterviewSolutions