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What is the equation of the plane through z-axis and parallel to the line (x-1)/costheta=(y+2)/sintheta=(z-3)/0? |
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Answer» `x COT THETA +y=0` `ac+by=0` It is given that this plane is PARELLEL to the line `(x-1)/costheta=(y+2)/SINTHETA=(z-3)/0` Since the plane parallel to the line `:. Acostheta=-bb sin theta=0` `rArr a cos theta =-b sin thetarArr a = -b tan theta` `:.-b tan thetax +by =0` `rArr x tan theta-y=0 (`:' b ne 0`) Which is REQUIRED equation of plane. |
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