What is the equilibrium concentration of each of the substances in the equilibrium when the intial concentration of ICI was 0*78 M ?

What is the equilibrium concentration of each of the substances in the

1.	What is the equilibrium concentration of each of the substances in the equilibrium when the intial concentration of ICI was 0*78 M ?
Answer» Solution :Suppose at EQUILIBRIUM , `[I_(2)] = [Cl_(2)] = x "mol" L^(-1) .`Then `{:(,2I Cl ,hArr,I_(2)(g),+,Cl_(2)(g)), ("Intial conc." ,078 "M",,0,,0), ("At eqm.",078 - 2 x,,x,,x):}` ` K_(c) = ([I_(2)][Cl_(2)])/([ICl]^(2)) :. 014 = (x xx x )/(078 - 2X)^(2) ` or ` x^(2) = 0* 14 (0* 78 - 2x)^(2) or x/(078-2x) = sqrt(014) = 0374 ` or `x = 0292 - 0748or 1748 x = 0* 291 or x = 0* 167` Hence, at equilibrium , ` [I_(2) ] = [Cl_(2)] = 0167 "M", [ICl ] =0 78 - 2 xx 0* 167 "M" = 0*446 "M"`