1.

What is the equilibrium expression for the reaction, P_(4(s)) + 5O_(2(g)) hArr P_(4)O_(10(s)) ? .

Answer»

`K_c = ([P_4O_(10)])/([P_4][O_2]^5)`
`K_c = 1/([O_2]^5)`
`K_c = [O_2]^5`
`K_c = ([P_4O_(10)])/(5[P_4][O_2])`

SOLUTION :`K=(1)/([O_(2)]^(5) xx 1)`


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