1.

What is the equilibrium expression for the reaction P_(4(s))+5O_(2(g))hArrP_(4)O_(10(s))

Answer»

`k_(c)=[O_(2)]^(5)`
`K_(c)=[P_(4)O_(10)]//[P_(4)][O_(2)]`
`K_(c)=[P_(4)O_(10)]//[P_(4)][O_(2)]^(5)`
`K_(c)=1//[O_(2)]^(5)`

Solution :`P_(4(s))+5O_(2(G))hArrP_(4)O_(10(s))`
`K_(c)=([P_(4)O_(10(s))])/([P_(4(s))][P_(2(g))]^(5))`
We know that CONCENTRATION of a solid compnent is always TAKEN as unity `K_(c)=(1)/([O_(2)]^(5))`


Discussion

No Comment Found

Related InterviewSolutions