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What is the equivalent weight of `P` in the following reaction? `P_(4)+NaOH rarr NaH_(2)PO_(2)+PH_(3)`A. `(31)/(4)`B. `(31)/(3)`C. `(31)/(2)`D. `31xx4//3` |
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Answer» Correct Answer - D `P_(4) rarr NaH_(2)PO_(2)` `(P_(4))^(@) rarr 4P^(+)+4e^(-)` `:. ` Eq. wt. (Reductant) `=(P_(4))/(4)` `(P_(4))^(@)+12e rarr 4p^(3-)` `:.` Eq.wt.(Oxidant)`=(P_(4))/(12)` `:.` Eq. wt. `(P_(4))=(P_(4))/(12)+(P_(4))/(12)` `=P_(4)xx(16)/(48)=(4xx31)/(3)=31xx(4)/(3)` |
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