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What is the equivalent weight of SnCl_(2) in the reaction, SnCl_(2) + Cl_(2) to SnCl_(4)? (mol.wt. of SnCl_(2)=190) |
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Answer» 95 EQ. wt. of `SnCl_(2)` = Eq. wt of `Cl_(2)` `therefore` (190)/(E_(1)= (71)/(35.5)` or `E_(1) =95` |
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