1.

What is the equivalent weight of SnCl_(2) in the reaction, SnCl_(2) + Cl_(2) to SnCl_(4)? (mol.wt. of SnCl_(2)=190)

Answer»

95
45
60
30

Solution :a) `SnCl_(2) + Cl_(2) to SnCl_(4)`
EQ. wt. of `SnCl_(2)` = Eq. wt of `Cl_(2)`
`therefore` (190)/(E_(1)= (71)/(35.5)` or `E_(1) =95`


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