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What is the equivalent weight of `SnCl_(2)` in the reaction, `SnCl_(2) + Cl_(2) to SnCl_(4)`? (mol.wt. of `SnCl_(2)`=190)A. 95B. 45C. 60D. 30 |
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Answer» a) `SnCl_(2) + Cl_(2) to SnCl_(4)` Eq. wt. of `SnCl_(2)` = Eq. wt of `Cl_(2)` `therefore` (190)/(E_(1)= (71)/(35.5)` or `E_(1) =95` |
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