Saved Bookmarks
| 1. |
What is the excess of pressure inside a spherical drop of water of radius 1mm. Surface tension of water is 70xx10^(-3)N//m. |
|
Answer» Solution :Radius of WATER drop, R = 1mm = `1xx10^(-3)m`, Surface tension of water, `T=70xx10^(-3)Nm^(-1)` Excess PRESSURE inside the drop, `P=(2T)/r=(2xx70xx10^(-3))/(1xx10^(-3))=140Nm^(-2)`. |
|