1.

What is the excess of pressure inside a spherical drop of water of radius 1mm. Surface tension of water is 70xx10^(-3)N//m.

Answer»

Solution :Radius of WATER drop, R = 1mm = `1xx10^(-3)m`, Surface tension of water, `T=70xx10^(-3)Nm^(-1)`
Excess PRESSURE inside the drop, `P=(2T)/r=(2xx70xx10^(-3))/(1xx10^(-3))=140Nm^(-2)`.


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