1.

What is the excess of pressure inside the spherical drop of water of radius 1mm. Surface tension of water is 70xx10^(-3)N//m.

Answer»

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SOLUTION :Radius of water drop, `R=1mm=1xx10^(-3)m`
SURFACE tension of water, `S=70xx10^(-3)Nm^(-1)`
EXCESS pressure inside the drop,
`P=(2S)/(r)=(2xx70xx10^(-3))/(1xx10^(-3))=140Nm^(-2)`.


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