What is the excess pressure inside a bubble of soap solution of radius 5.00 mm , given that the surface of soap solution at the temperature (20^(@)C) is 2.50xx10^(-2)Nm^(-1) ?If an air bubble of the same dimension were formed at depth of40.0 cm inside a container containing the soap solution (of relative density 1.20) , what would be the pressure is 1.01xx10^(5)Pa).

What is the excess pressure inside a bubble of soap solution of radius

1.	What is the excess pressure inside a bubble of soap solution of radius 5.00 mm , given that the surface of soap solution at the temperature (20^(@)C) is 2.50xx10^(-2)Nm^(-1) ?If an air bubble of the same dimension were formed at depth of40.0 cm inside a container containing the soap solution (of relative density 1.20) , what would be the pressure is 1.01xx10^(5)Pa).
Answer» SOLUTION :Excess pressure inside soap bubble , `P_(i)-P_(o)=(4S)/(R)=(4xx2.5XX10^(-2))/(5xx10^(-3))=20Pa` Excess pressure inside the soap bubble in air, `P_(i)-P_(o)=(2S)/(R)=(2xx2.5xx10^(-2))/(5xx10^(-3))=10Pa` Inside pressure air bubble at depth of 40 cm , `P_(i)=P_(0)+(2S)/(r)` `=1.01xx10^(5)+hrhog+(2S)/(r)` `=1.01xx10^(5)+0.4xx1.2xx10^(3)xx9.8+10` `=1.01xx10^(5)+4.704xx10^(3)+10` `1.01xx10^(5)+0.04704xx10^(5)+10` `=1.05704xx10^(5)PA+10Pa` `=1.06xx10^(5)Pa+0.00010xx10^(5)Pa` `=1.0601xx10^(5)Pa` `=1.06xx10^(5)Pa`