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What is the first address for customer 128 of group 2?(a) 190.100.127.128/26(b) 190.100.127.255/26(c) 190.100.127.128/25(d) 190.100.127.255/25I got this question in an interview.I would like to ask this question from Designing Subnets in section Internet Protocol, Network Addressing and Transport Level Security of Cryptograph & Network Security |
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Answer» Right option is (a) 190.100.127.128/26 |
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