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What is the force that a conductor \(\vec{dl}\) carrying a current I experiences, when placed in a magnetic field\(\vec B\), when its length is making an angle of 30˚ with the direction of field? |
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Answer» \(|\vec {dF}|=I|\vec{dl}\times \vec B|\) = I.dl.B sin30˚ = \(\frac{I\,dl.B}{2}\) |
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