What is the formula for the radius at the centre of gravity?(a) radius at the centre of gravity = inner diameter^1.5/6.3(b) radius at the centre of gravity = inner diameter^2/6.3(c) radius at the centre of gravity = outer diameter^1.5/6.3(d) radius at the centre of gravity = outer diameter^2/6.3The question was asked at a job interview.This intriguing question originated from Frames of D.C. & A.C. Machines in division Aspects of Design of Mechanical Parts of Design of Electrical Machines

What is the formula for the radius at the centre of gravity?(a) radius

1.	What is the formula for the radius at the centre of gravity?(a) radius at the centre of gravity = inner diameter^1.5/6.3(b) radius at the centre of gravity = inner diameter^2/6.3(c) radius at the centre of gravity = outer diameter^1.5/6.3(d) radius at the centre of gravity = outer diameter^2/6.3The question was asked at a job interview.This intriguing question originated from Frames of D.C. & A.C. Machines in division Aspects of Design of Mechanical Parts of Design of Electrical Machines
Answer» The correct choice is (c) RADIUS at the centre of GRAVITY = outer DIAMETER^1.5/6.3 To elaborate: The outer diameter of stator CORE is first CALCULATED. On substituting the values the radius at the centre of gravity is obtained.

Discussion

No Comment Found

Related InterviewSolutions

What is the additional setup provided to the simple thrust bearing when it is not able to take up radial loads?(a) ball bearing(b) gear bearing(c) steel bearing(d) guide bearingI got this question by my school principal while I was bunking the class.My enquiry is from Bearings in portion Aspects of Design of Mechanical Parts of Design of Electrical Machines
How are the radial loads caused?(a) dynamic unbalance of rotor(b) unbalanced magnetic pull of rotor(c) dynamic unbalance of rotor or unbalanced magnetic pull of rotor(d) dynamic unbalance of rotor and unbalanced magnetic pull of rotorThe question was asked in my homework.This intriguing question originated from Bearings in division Aspects of Design of Mechanical Parts of Design of Electrical Machines
What is the formula for the maximum air passing per second at maximum efficiency?(a) maximum air passing = 2 * volume of air passing per second(b) maximum air passing =volume of air passing per second(c) maximum air passing = 2 / volume of air passing per second(d) maximum air passing =volume of air passing per second / 2This question was posed to me in a national level competition.I want to ask this question from Design of Fan in division Aspects of Design of Mechanical Parts of Design of Electrical Machines
What is the formula for the number of blades?(a) number of blades = 3.14 * outside diameter * (1.25 – 1.5)* width of fan(b) number of blades = 3.14 / outside diameter * (1.25 – 1.5)* width of fan(c) number of blades = 3.14 * outside diameter / (1.25 – 1.5)* width of fan(d) number of blades = 3.14 * outside diameter * (1.25 – 1.5) / width of fanThe question was asked in my homework.The query is from Design of Fan in section Aspects of Design of Mechanical Parts of Design of Electrical Machines
What is the formula of the width of fan?(a) width of fan = area of outlet opening * 2.88 * outside diameter */ coefficient of utilization(b) width of fan = 1/ area of outlet opening * 2.88 * outside diameter * coefficient of utilization(c) width of fan = area of outlet opening * 2.88 * outside diameter * coefficient of utilization(d) width of fan = area of outlet opening / 2.88 * outside diameter * coefficient of utilizationI got this question in unit test.Question is taken from Design of Fan topic in chapter Aspects of Design of Mechanical Parts of Design of Electrical Machines
What is the formula for the area of outlet opening?(a) area of outlet opening = maximum air passing per second / 0.42 * peripheral speed(b) area of outlet opening = maximum air passing per second * 0.42 * peripheral speed(c) area of outlet opening = maximum air passing per second * 0.42 / peripheral speed(d) area of outlet opening = 1/maximum air passing per second * 0.42 * peripheral speedThis question was posed to me by my college director while I was bunking the class.The origin of the question is Design of Fan in division Aspects of Design of Mechanical Parts of Design of Electrical Machines
What is the range of the difference of air temperature at inlet and outlet?(a) 11-15^0C(b) 10-13^0C(c) 12-16^0C(d) 14-18^0CI had been asked this question in examination.Origin of the question is Design of Fan in division Aspects of Design of Mechanical Parts of Design of Electrical Machines
What is the formula for the volume of air?(a) volume of air = 0.9 * losses in kW / difference of air temperature at inlet and outlet(b) volume of air = 0.9 * losses in kW * difference of air temperature at inlet and outlet(c) volume of air = 0.9 / losses in kW * difference of air temperature at inlet and outlet(d) volume of air = 1 / 0.9 * losses in kW * difference of air temperature at inlet and outletThe question was posed to me in quiz.Asked question is from Design of Fan topic in chapter Aspects of Design of Mechanical Parts of Design of Electrical Machines
How many steps are required in the design of the fan?(a) 7(b) 8(c) 9(d) 6The question was posed to me in examination.My enquiry is from Design of Fan in chapter Aspects of Design of Mechanical Parts of Design of Electrical Machines
How many data are required for the design of fan?(a) 3(b) 4(c) 5(d) 6I had been asked this question by my college professor while I was bunking the class.My question is taken from Design of Fan topic in chapter Aspects of Design of Mechanical Parts of Design of Electrical Machines

Discussion

No Comment Found

Related InterviewSolutions

Reply to Comment