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What is the formula of compound present in brown ring? |
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Answer» SOLUTION :`3FE^(2+)+NO_(3)^(ɵ)+4H^(o+)to3Fe^(2+)+NO+2H_(2)O` `FeSO_(4)+NOtoFeSO_(4).NO` or `[Fe(H_(2)O)_(5)NO]SO_(4)` |
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