1.

What is the formula of compound present in brown ring?

Answer»

SOLUTION :`3FE^(2+)+NO_(3)^(ɵ)+4H^(o+)to3Fe^(2+)+NO+2H_(2)O`
`FeSO_(4)+NOtoFeSO_(4).NO` or `[Fe(H_(2)O)_(5)NO]SO_(4)`


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