1.

What is the free energy change for the half reaction Li^(+) + e^(-) to Li ? Given E_(LI^(+) | Li)^(@) = -3.0 V , F = 96500 C mol^(-1) and T = 298 K

Answer»

`298.5 kJ mol^(-1)`
`-298.5 kJ mol^(-1)`
`32.166 CV^(-1) mol^(-1)`
`-289500 CV mol^(-1)`

Solution :`DELTA G ^(@) = - N FE^(@) = - 1 xx 96500 xx (-3.0) J = 289.5kJ`.


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