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What is the frequency and wavelength of a photon emitted during a transition form n2=5 state N1=2 state of hydrogen atom. |
Answer» <html><body><p>The frequency is nothing but c/& as speed=frequency <a href="https://interviewquestions.tuteehub.com/tag/times-1420471" style="font-weight:bold;" target="_blank" title="Click to know more about TIMES">TIMES</a> wavelength. <a href="https://interviewquestions.tuteehub.com/tag/thus-2307358" style="font-weight:bold;" target="_blank" title="Click to know more about THUS">THUS</a>, Energy = Planck's constant(<a href="https://interviewquestions.tuteehub.com/tag/h-1014193" style="font-weight:bold;" target="_blank" title="Click to know more about H">H</a>)*frequency(v). According to your case, the electron is in a transition <a href="https://interviewquestions.tuteehub.com/tag/state-21805" style="font-weight:bold;" target="_blank" title="Click to know more about STATE">STATE</a> from n=5 to n=2. So, the <a href="https://interviewquestions.tuteehub.com/tag/total-711110" style="font-weight:bold;" target="_blank" title="Click to know more about TOTAL">TOTAL</a> energy during the transition is given by E(net) = E(at state 5) - E(at state 2).</p></body></html> | |