1.

What is the frequency of photon, whose momentum is 1.1xx10^(-23) kg ms^(-2)

Answer»

`5xx10^16` HZ
`5xx10^17` Hz
`0.5xx10^18` Hz
`5xx10^18` Hz

Solution :`because E=mc^2, E=HV`
`therefore mc^2 =hv`
`v=(mc^2)/(h)=(1.1xx10^(-23)xx3xx10^8)/(6.6xx10^(-34))=5xx10^18` Hz


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