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What is the full order of atomisation enthalpy in 3d series?​

Answer» <html><body><p></p><p>The enthalpy of atomization depends on the extensive metallic <a href="https://interviewquestions.tuteehub.com/tag/bonding-900657" style="font-weight:bold;" target="_blank" title="Click to know more about BONDING">BONDING</a> which in turn depends on the number of <a href="https://interviewquestions.tuteehub.com/tag/unpaired-7721036" style="font-weight:bold;" target="_blank" title="Click to know more about UNPAIRED">UNPAIRED</a> electrons. <a href="https://interviewquestions.tuteehub.com/tag/due-433472" style="font-weight:bold;" target="_blank" title="Click to know more about DUE">DUE</a> to the absence of these unpaired electrons in <a href="https://interviewquestions.tuteehub.com/tag/zn-751409" style="font-weight:bold;" target="_blank" title="Click to know more about ZN">ZN</a>. The interatomic bonding is weak in Zn and <a href="https://interviewquestions.tuteehub.com/tag/hence-484344" style="font-weight:bold;" target="_blank" title="Click to know more about HENCE">HENCE</a> the enthalpy of atomization of Zn is the lowest.</p></body></html>


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